# implementa — IAlgebra

> IAlgebra (iPhone/iPad app by 斌 朱.)

- Source: https://appshunter.io/ios/app/implementa/id1558334767 (this page in markdown: same URL + `.md`)
- Developer: [斌 朱](https://appshunter.io/developer/1461805000)
- Category: Education, Utilities
- Price: Free
- Age rating: 4+
- Requires: iOS 15.0 · 53 MB
- Languages: American English
- Released: 2021-03-16
- Data updated: 2026-03-12
- User reviews in markdown: https://appshunter.io/ios/app/implementa/id1558334767/reviews.md

## What is implementa?

The App provides users with a learning platform to explore and solve algebra f(x) exercises. In each step of problem solving, by selecting the mathematical operation provided by the App, users can complete the problem-solving in exploration and learning like a driver controlling the steering wheel, master the concept of algebra in the integration of knowledge and action, and gain the ability to use concepts and knowledge to solve problems. If you want the answer, you can use a group of Ai. If you want the ability, you can try IA to make carbon-based life smarter! Not GPUs.
App 提供用户一个探索求解代数f(x)习题的学习平台。在解题的每一步，通过选择App提供的数学操作，用户如车手操控方向盘般，在探索学习中完成解题, 在知行合一中掌握代数的概念，获得运用概念与知识解决问题的能力。你想要答案，可以用一众Ai，你想要能力，可以试试IA，让碳基生命更智能！而不是GPU们。


## Version history (last 5 releases)

### 10 — 2025-11-10

1. (a+b-c)(a-b+c) =(a+(b-c))(a-(b-c))
2. a()+b() remove parentheses and merge similar terms
3. Calculate the value of the independent variable of the function, such as f(1/3+1/6)+f(1/3-1/6)=f(1/3)f1/6), get f(1/2)+f(1/6)=f(1/3)f1/6
4. Move the terms of various equations together and combine the similar terms.
5. Calculate the value of the root
6. Calculate the value of the discrimination formula of the root
7. Simplify the result of simplified (a+b)^2
8. Simplify the result of  multiplying same algebraic formula  on both sides of the equation
9. Reduce the equations/inequalities generated by retaining intermediate calculation results
10. a/b>n>0, directly use the relevant properties of a/b>0, support n>a>=0, n>b>0
11. Add the equality u=(x+1)/(x-1) when making an introduction to the classification of log_a (x+1)/(x-1) > 1
12. Support f(f(x)) as the usage of replaceing unknown, so that t=f(x)
13. Input and execute, no need to click the selection again.
14. Provide a vertical list display of existing equations/inequalities
15. Click on the color topic to see the explanation of relevant concepts.
16. Other errors and bugs: iPad input interception, the operation does not match its interpretation, and the standard judgment of quadratic equations is not strict.
1. (a+b-c)(a-b+c) =(a+(b-c))(a-(b-c))
2. a()+b()去括号并合并同类项
3. 计算函数自变量的值，例如f(1/3+1/6)+f(1/3-1/6)=f(1/3)f1/6),得f(1/2)+f(1/6)=f(1/3)f1/6
4. 对各类方程一并移项并合并同类项
5. 计算根的值
6. 计算根的判别式的值
7. 简化（a+b）^2的结果
8. 简化等式两边同乘代数式的结果
9. 减少保留中间计算结果产生的等式/不等式
10. a/b>n>0, 直接使用a/b>0 的相关性质，支持 n>a>=0, n>b>0
11. 对 log_a (x+1)/(x-1) > 1 做分类导论时增加换元u=(x+1)/(x-1)
12. 支持f(f(x))做还元的用法，令t=f(x)
13. 输入即可执行，不需要再点选择项
14. 提供已有等式/不等式的垂直列表显示
15. 点击彩色题目可看相关概念解释
16. 其它错误与bug: ipad 输入拦截，操作项与其解释不匹配，二次方程标准型判定不严格

### 9 — 2025-08-28

1.Support dark mode.
2.The menu only provides operations that can be performed and need to be performed to reduce information overload.
3.For operations that require inputting algebraic formulas, after completing the input, you need to click on the selected algebraic formula, equal sign, and inequality sign to perform the operation. All other operations can be executed after selecting the correct answer.

1.支持深色模式。
2.菜单中仅提供能被执行与需要执行的操作，减少信息过载。
3.对于需要输入代数式的操作，完成输入后需要再点击选择的代数式、等号、不等号，以便执行操作，
其它所有操作选中正确答案后即可执行操作。

### 8 — 2025-02-21

1. System framework: Support to go back to the previous step in the review problem-solving process mode
2. Algebra: Substitute eligible numbers into letters, and observe and find the quantitative relationship.
3. Function: If there is f(x), then x conforms to the definition,
Substitute any algebraic formula that meets the definition into the independent variable of the function to get the function value.
Substitute algebraic expressions into the relevant function independent variables of the inequality
Subset functions inherit the quantitative relationship of parent functions
 converted f(u(x))  to f(v(x)), for example, convert f(f(x)) to f(t),convert  f(t) to f(f(x))
4. Function monotony
Judge the size of the function value according to the size of the expression
Judge the size of the independent variable according to the value size of the function
Exponential functions, logarithmic functions and other standard functions are classified and discussed according to monotony.
Construct the function value size relationship of any pair of numbers in the definition domain
Get the maximum and minimum values of the closed interval monotonous function
Greater than the maximum value of the function greater than the function
Less than the minimum value of the function less than function
Let the function of two\three sides of the inequality become an isomorphic function.
Determining the monotony of the function includes judging the monotonicity of the function.
5. Judge the oddity of the function
6. The operation properties of logarithms
Construct and judge the symbol of N-1 to judge the symbol of log_a N
Other algebraic formulas that are known to be complied by co-multiplication on both sides of the inequality,
Compare the size of the related quantities of two equations and judge the symbol of the multi-factor product,
Clear some bugs, including problem-solving framework boundaries\exit and re-entry-related bugs

1.系统框架:在复习解题过程模式中支持回退到上一步
2.代数:代入符合条件的数到字母中,观察发现数量关系
3.函数:存在f(x),则x符合定义,
   代入任意符合定义的代数式到函数的自变量中求函数值
   代入代数式到不等式的相关函数自变量中
   子集函数继承父集函数的数量关系
   f(u(x))转换为f(v(x)）,例如f(f(x))转换位f(t),f(t)转换位f(f(x))
4.函数单调性
  依据表达式大小判断函数值大小
  依据函数值大小判断自变量大小
  指数函数、对数函数等标准函数按单调性分类讨论
  构造定义域上的任意一对数的函数值大小关系
  闭区间单调函数的最大值与最小值
  大于函数大于函数的最大值
  小于函数小雨函数的最小值
  让不等式两\三边的函数式成为同构函数
  判定函数的单调性包括由函数单调判断函数的增减性
5.判断函数的奇偶性
6.对数的运算性质
   构造并判断N-1的符号以判断log_a N 的符号
   
 其它 不等式两边同乘已知符合的代数式,
         比较两个等式相关数量的大小,判断多因式乘积的符号,
         清除一些bug,包括解题框架边界\退出重入相关的bug

### 7 — 2024-02-13

Simplify the easy computing to reduce steps of implementing
add content: 
  abstract function f(x)  
  one Variable Quadratic Equation
  compound inequaliy
  classification
  proof by contradiction/reduction 
to make nature inequality m>n(m-n>0)
to make inequality from m>n>0 to sqrt(m)>sqrt(n)  
refine relative formula about the addition of rational number
refine solution judge to use compound ineqaulity
Clear other errors and bugs

简化简单计算以大量减少解题步骤
新增内容：
    抽象函数f(x)
    一元二次方程
    复合不等式
    分类讨论
    反证法
支持不等于不等式， 
支持构造自然不等式 m>n(m-n>0)
支持从m>n>构造不等式sqrt(m)>sqrt(n)
改进有数加法相关规则的运用
改进不等式解集判定支持复合不等式
清除其它错误与bugs

### 6.4 — 2023-06-16

Support user to know the introduction  of math-operation selected by tap the name displayed
Support user to know the introduction  of math-operation by tap item of operation list in my page
Add content in how page to introduce how to get introduction info of math-operation
Refine the display of complicated fraction
Refine the display of complicated radial

支持用戶點觸已經選擇的數學操作名稱以查看操作相關的介紹
支持用戶點觸我的頁面的操作清單中數學操作名稱以查看操作相關的介紹
在用法頁增加內容介紹如何查看數學操作的相關介紹

支持用戶点触已经選选择的数学操作名称以查看操作相关的介绍
支持用戶点触我的页面的操作清单中数学操作名称以查看操作相关的介绍
在用法页面增加内容介绍如何查看数学操纵的相关 介绍

## More apps by 斌 朱

- [clickgetx](https://appshunter.io/ios/app/clickgetx/id6756349401)

All apps by 斌 朱: https://appshunter.io/developer/1461805000

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*Data collected daily from the US App Store and indexed by [AppsHunter](https://appshunter.io/). User reviews are verbatim App Store reviews. Ratings, prices and chart positions refresh continuously; this snapshot is from 2026-03-12.*