# Goldbach's Conjecture vs e++ Algebraic Tiles

The clearest difference is price: e++ Algebraic Tiles at Free against Goldbach's Conjecture's $0.99. On ads, in-app purchases, device support and iOS requirement there is nothing between them.

e++ Algebraic Tiles is free to download; Goldbach's Conjecture costs $0.99 up front. Neither carries in-app purchases, so what you see is what you pay.

## The numbers

| Metric | Goldbach's Conjecture | e++ Algebraic Tiles |
| --- | --- | --- |
| Price | $0.99 | **Free** |
| In-app purchases | No | No |
| Ads | No | No |
| Update frequency | Every 8 months | — |
| Size | 34 MB | 5 MB |
| Requires iOS | **12.0** | 13.0 |
| Devices | **iPad, Mac** | iPad |
| Age rating | 4+ | 4+ |
| Developer | [Ventura Educational Systems](https://appshunter.io/developer/371324172) | [Modern Educational Research Society, LTD](https://appshunter.io/developer/432268704) |

## What reviewers say

### Goldbach's Conjecture

[App page](https://appshunter.io/ios/app/goldbachs-conjecture/id1385243580)

**In-app purchases:** none


### e++ Algebraic Tiles

[App page](https://appshunter.io/ios/app/e-plus-plus-algebraic-tiles/id1601364386)

**Features:** macOS Compatibility

**In-app purchases:** none


## Frequently asked questions

### Is Goldbach's Conjecture free?

Goldbach's Conjecture costs $0.99, with no in-app purchases.

### Is e++ Algebraic Tiles free?

e++ Algebraic Tiles is free to download, with no in-app purchases.

### Do Goldbach's Conjecture or e++ Algebraic Tiles have ads?

Neither Goldbach's Conjecture nor e++ Algebraic Tiles shows ads.

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*Compared by [AppsHunter](https://appshunter.io/) from daily US App Store data. Review summaries are generated from verbatim App Store reviews.*