About Aventura e Adrenalina
- Released
- Updated
- iOS Version
- Age Rating
- Size
- Devices
- Languages
Features
Developer of Aventura e Adrenalina
What's New in Aventura e Adrenalina
1.0.5
September 14, 2024
- Validando obrigatóriedade na seleção de camisetas
Alternatives to Aventura e Adrenalina
More Applications by Carlos Eduardo Sonego
FAQ
Is Aventura e Adrenalina available on iPad devices?
Yes, Aventura e Adrenalina is compatible with the iPad.
Who is the app developer of Aventura e Adrenalina?
Carlos Eduardo Sonego built the Aventura e Adrenalina app.
What is the minimum iOS version supported by Aventura e Adrenalina?
The minimum supported iOS version for the app is 12.0.
What user rating does the Aventura e Adrenalina app have?
Currently, there are no ratings to display for the Aventura e Adrenalina.
What’s the genre of the Aventura e Adrenalina app?
The App Genre Of Aventura E Adrenalina Is Sports.
What is the current version of Aventura e Adrenalina?
1.0.5 is the latest released Aventura e Adrenalina version.
What is the latest update date for Aventura e Adrenalina?
Aventura e Adrenalina’s latest update was rolled out on December 4, 2024.
Could you provide information on the release date of Aventura e Adrenalina?
The app was launched on March 22, 2023.
What is the content advisory rating for the Aventura e Adrenalina app?
Family-friendly content, no mature themes or violence.
What languages does the Aventura e Adrenalina app support?
The Aventura e Adrenalina app is now available in American English.
Is Aventura e Adrenalina one of the titles available through Apple Arcade?
No, Aventura e Adrenalina is not part of Apple Arcade.
Does Aventura e Adrenalina feature in-app purchases?
No, you won't find in-app purchases featured in Aventura e Adrenalina.
Is Aventura e Adrenalina optimized for use with Apple Vision Pro?
Unfortunately, Aventura e Adrenalina is not optimized for use with Apple Vision Pro.
Are there any advertisements in Aventura e Adrenalina?
No, there are no advertisements in Aventura e Adrenalina.