Comparison

Shortcut Rush vs Hexagonal Run!

Price, ratings, monetisation and update history for both games, side by side โ€” with what reviewers say about each.

Head to head
About

Shortcut Rush

Features
Read full description

Shortcut Rush Race fun game to play, collect tiles while running towards the finish line.Use the tiles to create bridge over the water to to rush to the finish line

About

Hexagonal Run!

Features
Read full description

Challenging game where you must build bridges to reach the end first. Your character automatically moves forward, and you can swipe right and left to rotate the character. Collect elements on the floor to make bridges!

Screenshots

Shortcut Rush4 screens
Hexagonal Run!3 screens

Verdict

The call

The clearest difference is ads: Shortcut Rush at none against Hexagonal Run!'s shown. On price, in-app purchases, device support and iOS requirement there is nothing between them.

Scored on Price ยท Rating ยท Positive reviews ยท Number of ratings ยท Update frequency ยท Ads ยท In-app purchases ยท Monetization ยท Best chart rank ยท Devices ยท Requires iOS

CostPrice ยท In-app purchases ยท Ads ยท Monetization

Both are free to download. Neither carries in-app purchases, so what you see is what you pay.

Scorecard1 real difference ยท 5 level
Shortcut Rush versus Hexagonal Run!: the parameters behind the verdict, then further details
ParameterShortcut RushHexagonal Run!
PriceFreeFree
Update frequencyEvery 2 daysโ€”
AdsNo โ€” betterYes
In-app purchasesNoNo
DevicesiPhone, iPad, iPodiPhone, iPad, iPod
Requires iOS12.012.0
Further details โ€” not scored
Size133 MB103 MB
Age rating4+17+
Developerelias sleimanMarco Andreotti

In-app purchases

None

Shortcut Rush

No in-app purchases

None

Hexagonal Run!

No in-app purchases

Questions

Is Shortcut Rush free?
Shortcut Rush is free to download, with no in-app purchases.
Is Hexagonal Run! free?
Hexagonal Run! is free to download, with no in-app purchases.
Do Shortcut Rush or Hexagonal Run! have ads?
Hexagonal Run! shows ads; Shortcut Rush does not.

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